Quantcast
Channel: Mathelounge - Neue Fragen und Antworten
Viewing all articles
Browse latest Browse all 216858

Beantwortet: Wahrscheinlichkeit: Stehzeit an Ampel

$
0
0

p(X≥43) = 1 - p(x<42) = 1 - phi( (43-40)/2 ) = 1 - phi(1,5) = 6,7%

p( x≤36)= p(x<37) = phi( (37-40)/2) = phi ( -1,5) = 6,7%

p( 36<x<44) = phi(2) - phi(-2) = 0,9772 - 0,0228 = = 95,4 %


Viewing all articles
Browse latest Browse all 216858

Trending Articles



<script src="https://jsc.adskeeper.com/r/s/rssing.com.1596347.js" async> </script>