reflexiv hieße (x;y) ist mit sich selbst in Relation, also
r*(x-x) = s(y-y)
r*0 = s*0
Das stimmt offenbar. Also reflexiv.
↧
Beantwortet: Reflexivität zeigen (Relation)
↧
Channel:
Mathelounge - Neue Fragen und Antworten
X
Are you the publisher?
Claim or
contact us
about this channel.
X
No ratings yet.
Channel Details:
- Title: Mathelounge - Neue Fragen und Antworten
- Channel Number: 53303081
- Language: German
- Registered On: September 14, 2015, 4:01 pm
- Number of Articles: 216858
- Latest Snapshot: June 21, 2025, 10:04 am
- RSS URL: http://www.mathelounge.de/feed/qa.rss
- Publisher: https://www.mathelounge.de/qa
- Description: Powered by Question2Answer
- Catalog: //mathelounge8.rssing.com/catalog.php?indx=53303081
© 2025 //www.rssing.com