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Beantwortet: Wie stelle ich i = (n1-ns)/(n4-ns) nach ns um?

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Hallo,

Mal (n4 -ns)

i(n4 -ns)= n1 -ns

i *n4 -i*ns= n1 -ns |+ns

i *n4 -i*ns +nS=n1 |-in4

 -i*ns +nS=n1 -in4

ns(1-i))=n1 -in4

ns= (n1 -in4)/(1-i)


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