Beantwortet: Nullproduktsatz. 0= ( 2x+4)* (-2/3x²-x+1)

(2·x + 4)·(- 2/3·x^2 - x + 1) = 0

2·x + 4 = 0 --> x = -4/2 = -2

- 2/3·x^2 - x + 1 = 0

x^2 + 3/2·x - 3/2 = 0

x = - 3/4 ± √(9/16 + 24/16) = x = - 3/4 ± √33/4

x1 = -2.1861 ∨ x2 = 0.6861