lim (n --> ∞) n^(1/2)·(n^(1/n) - 1)
= lim (n --> ∞) n^(1/2 + 1/n) - √n
= lim (n --> ∞) √n - √n = 0
↧
Beantwortet: Konvergenz dieser Folge untersuchen. an: = √n (^n√(n) - 1)
↧
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