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Beantwortet: Doppelbrüche vereinfachen: (4·a·b/(3·x) - 2·b/(4·x))/(8·a·b/x - b/(3·x))

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weil Weihnachten war einmal richtig schön:

$$ \frac { \frac { 4ab }{ 3x } -\frac { 2b }{ 4x }}{\frac { 8ab}{ x }-\frac { b }{ 3x }} $$
$$ =\frac { \frac { 16ab }{ 12x } -\frac { 6b }{ 12x }}{\frac { 24ab}{ 3x }-\frac { b }{ 3x }} $$
$$ =\frac { \frac { 16ab -6b}{ 12x } }{\frac { 24ab-b}{ 3x }} $$
$$ =\frac { (16ab -6b)*3x} {12x*( 24ab-b)} $$
$$ =\frac { (16ab -6b)} {4*( 24ab-b)} $$
$$ =\frac { 2b(8a -3)} {4b( 24a-1)} $$
$$ =\frac { 8a -3} {2( 24a-1)} $$
$$ =\frac { 8a -3} {48a-2} $$


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